알고리즘 공부
백준 신입 사원
컴퓨터과학
2023. 8. 6. 12:37
https://www.acmicpc.net/problem/1946
1946번: 신입 사원
첫째 줄에는 테스트 케이스의 개수 T(1 ≤ T ≤ 20)가 주어진다. 각 테스트 케이스의 첫째 줄에 지원자의 숫자 N(1 ≤ N ≤ 100,000)이 주어진다. 둘째 줄부터 N개 줄에는 각각의 지원자의 서류심사 성
www.acmicpc.net
음 그리드 문제는 for문 하나로 무조건 해결해야 시간초과가 안나네요. 흐음 이게 제일 어렵네요
구현은 해도 시간복잡도가 항상 O(N)을 유지해야하네요.
#include <iostream>
#include <vector>
#include <queue>
#include<string>
#include<algorithm>
#include<cmath>
#include<unordered_map>
#include<map>
#include<stack>
using namespace std;
struct Point {
int s, e, t, cnt, power;
char c;
};
void Prints(vector<vector<int>>maps, int n, int m) {
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
cout << maps[i][j] << " ";
}
cout << endl;
}
cout << endl;
}
void Prints(vector<vector<bool>>maps, int n, int m) {
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
cout << maps[i][j] << " ";
}
cout << endl;
}
cout << endl;
}
void Prints(vector<vector<char>>maps, int n, int m) {
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
cout << maps[i][j];
}
cout << endl;
}
cout << endl;
}
void Prints(vector<vector<vector<char>>>maps, int n, int m, int k) {
for (int t = 0; t < k; t++) {
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
cout << maps[t][i][j];
}
cout << endl;
}
cout << endl;
}
cout << endl;
}
void Prints(vector<vector<vector<bool>>>maps, int n, int m, int k) {
for (int t = 0; t < k; t++) {
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
cout << maps[t][i][j];
}
cout << endl;
}
cout << endl;
}
cout << endl;
}
void Prints(vector<int>line, int n) {
for (int i = 0; i < n; i++) {
cout << line[i] << ",";
}
cout << endl;
}
void Prints(string str, int n) {
for (int i = 0; i < n; i++) {
cout << str[i] << ",";
}
cout << endl;
}
bool checkmaps(vector<vector<int>>maps, vector<vector<int>>anw, int n, int m) {
bool bCheck = false;
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
if (maps[i][j] != anw[i][j]) {
bCheck = true;
i = n + 1;
j = m + 1;
continue;
}
}
}
return bCheck;
}
bool findstart(vector<vector<int>>maps, vector<vector<int>>anw, int n, int m, int) {
bool bCheck = false;
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
if (maps[i][j] != anw[i][j]) {
bCheck = true;
i = n + 1;
j = m + 1;
continue;
}
}
}
return bCheck;
}
struct Data {
int resume;
int meeting;
int id;
bool bCheck = false;
};
struct GDatas {
int change;
int index;
string times;
};
void Prints(vector<Data>line, int n) {
for (int i = 0; i < n; i++) {
cout << line[i].id<<","<<line[i].meeting<<","<<line[i].resume << ","<<endl;
}
cout << endl;
}
long long n, m;
int k, x;
vector<vector<int>>glistmaps;
vector<bool>bVisited;
bool resumecmp(const Data &a, const Data &b) {
return a.resume < b.resume;
}
bool meetcmp(const Data &a, const Data &b) {
return a.meeting < b.meeting;
}
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
//
int T;
cin >> T;
vector<int>gCoutnt;
for (int z = 0; z < T; z++) {
int n;
cin >> n;
vector<Data>initlists;
vector<Data>lists;
vector<Data>srlists;
vector<Data>smlists;
int gcnt = 0;
for (int i = 0; i < n; i++) {
int resume;
int meeting;
cin >> resume>>meeting;
Data d;
d.id = i;
d.resume = resume;
d.meeting = meeting;
initlists.push_back(d);
}
lists=initlists;
sort(lists.begin(), lists.end(), resumecmp);
srlists = lists;
Data min = srlists[0];
gcnt++;
for (int i = 0; i < srlists.size(); i++) {
if (min.meeting > srlists[i].meeting) {
min = srlists[i];
gcnt++;
}
}
gCoutnt.push_back(gcnt);
}
for (int i = 0; i < gCoutnt.size(); i++) {
cout << gCoutnt[i] << endl;
}
return 0;
}